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Verified Answer :

Radius,r=8√3 m

Height of triangle ,h=2r ⇒ 16√3 m

Side of the triangle ,a=16√3/sin60 ⇒ 32 m

Area of the triangle,

A=√3/4(a²)

A =√3/4(32²)

A =443.4 m²

Answer:

The area of an equilateral triangle is \(83.13m^2\).

Step-by-step explanation:

Given: The radius of an equilateral triangle is 8m.

To find: The area of an equilateral triangle.

Solution: It is given that the radius of an equilateral triangle is 8m.

Now, height of the triangle is given as:

\(h=2r\)

Substituting the value of r, we have

\(h=2(8)\)

\(h=16m\)

The side of the triangle is given as:

\(a=hsin(60^{\circ})\)

\(a=16(sin60^{\circ})\)

\(a=16(\frac{\sqrt{3}}{2})\)

\(a=8\sqrt{3}m\)

Now, the area of an equilateral triangle is given as:

\(Area=\frac{\sqrt{3}}{4}(a^2)\)

\(Area=\frac{\sqrt{3}}{4}(8\sqrt{3})^2\)

\(Area=\frac{\sqrt{3}}{4}{\times}64{\times}3\)

\(Arae=48\sqrt{3}m^2\)

\(Area=83.13m^2\)

Therefore, the area of an equilateral triangle is \(83.13m^2\).