Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.
You use the formula:
A = angles/360pir^2
A = 32/360pi8.5^2 = 0.279 72.25= 20.15775 rounded to 20.2
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Answer:
The area of sector is 20.2 millimeter².
Step-by-step explanation:
The formula for area of sector is
\(A=\pi r^2\times (\frac{\theta}{360})\)
The central angle of the sector is 32° and the radius of the circle is 8.5 millimeters.
\(A=\pi\times (8.5)^2\times (\frac{32}{360})\)
\(A=\pi\times (6.42222222222)\)
\(A=20.1760061531\)
\(A\approx 20.2\)
Therefore the area of sector is 20.2 millimeter².