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Given that the function is:

y=a cos( bx+c), or y=a sin(x+c)

then the period is calculated as T= 2π/b and if T=2:

2=2π/b
b=2π/2=π

Therefore, the correct answer is option B, y=3 cos πx.

Hope this answers the question. Have a nice day.

isyllus

Answer:

B is correct.

Function y=3cos(πx) would be period 2.

Step-by-step explanation:

We are given a trigonometric equation. We need to find the function whose period is 2.

\(y=a\cos(bx+c)\)

Where,

a is amplitude of function.

b is wavelength of function.

c is phase shift of function.

As we know the period of y=cos x is 2π

So, Period of function, y=cos(ax) would be \(\frac{2\pi}{a}\)

If we divide 2π by coefficient of x we get period of function.

We are given period is 2

\(\text{Coefficient of x}=\frac{2\pi}{2}\)

\(\text{Coefficient of x}=\pi\)

Thus, B is correct. Function y=3cos(πx) would be period 2.

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