From 5 employees at a company, a group of 3 employees will be chosen to work on a project. How many different groups of 3 employees can be chosen?
Hello,
aPb=b(b-1)(b-2)....(b-a+1) / a!
3P5=543/(321)=10
If we name the number of the employers 1,2,3,4,5
Here are the choices:
123,124,125,134,135,145,234,235,245,345 (total 10 choices)
Based on the problem above the answer is 10. Below is the solution:
formula is 5! / 3! (5-3)! = 54321 / 32*2 = 10 combinations
There are 10 combination that are from 5 employees taken 3 at a time.