Verified Answer :

The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41

x=41
(x+1)=41+1=42
(x+2)=41+2=43

Answer: the three consecutive integers would be: 41,42 and 43. 

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