Answer:
Paul bought 3 Tee shirts and 6 Shirts.
Step-by-step explanation:
Given : Paul bought 9 total shirts for a total of $72.
Tee shirts cost $10 and long sleeve shirts cost $7.
To Find: How many of each type of shirt did he buy?
Solution:
Let x be the number of Tee
Let y be the number of long sleeve shirts
Now we are given that he bought 9 total shirts
So, @@MATH_TOKEN_0@@ --1
Cost of 1 Tee shirt = $10
So, Cost of x T shirts =10x
Cost of y long sleeve shirts = 7y
Since we are given that Paul bought 9 total shirts for a total of $72
So,Equation becomes: \(10x+7y=72\) --2
Solving 1 and 2
Substitute the value of x from 1 in 2
\(10(9-y)+7y=72\)
\(90-10y+7y=72\)
\(90-3y=72\)
\(18=3y\)
\(\frac{18}{3}=y\)
\(6=y\)
Now substitute the value of y in 1
\(x+6=9\)
\(x=3\)
So, Paul bought 3 Tee shirts and 6 Shirts.
