cindy1994090 cindy1994090

26-09-2016
Mathematics

Answered

Determine whether the sequence converges or diverges.

If it converges, find the limit. an=ln(2n^2 +1) - ln(n^2 +1)

Verified Answer :

26-09-2016

Hello,
\($ \lim_{x \to \infty} Ln(\frac{2x^2+1}{x^2+1}) =Ln(2)\)

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