Answer:
When she experiences 10 g's its speed is \(34.293\frac{m}{s}\)
Explanation:
I add a graph of the situation.
The centripetal acceleration (in this case 10 g's) is equal to the square of the speed ''V'' divided by the length ''r'' of the centrifuge arm.
\(ca=\frac{V^{2}}{r}\) (I)
If we replace all the data in the equation (I) :
\(98\frac{m}{s^{2}}=\frac{V^{2}}{12m}\)
\(V^{2}=1176\frac{m^{2}}{s^{2}}\)
\(V=34.293\frac{m}{s}\)
In the graph, I added the centripetal acceleration ''ca'', the acceleration ''a'', the velocity vector ''V'' which magnitude is the speed ''V'' and the tangential acceleration ''ta''.
