Answer:
Solution :
To solve the above equation we will follow the BODMAS rule.
- >> BODMAS is an order of mathematic operations.
- >> BODMAS rule is to be followed while solving expressions in mathematics.
It stands for :
\(\quad\begin{gathered} \small \begin{array}{l} \star \: \rm B= bracket \\\star \: \rm O= order \: of \: power \: \\\star \: \rm D= division \\\star \: \rm M= multiplication \\ \star \: \rm A= addition \\ \star \: \rm S=subtraction \end{array}\end{gathered}\)
Solving the questions by bodmas rule :
\(1) \: \pmb{\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}\)
\(= {\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}\)
\(= {\sf{(6 + \sqrt{25} ) \div ( {(3 \times 3)} + 2) }}\)
\(= {\sf{(6 + \sqrt{5 \times 5} ) \div ( 9 + 2) }}\)
\(= {\sf{(6 + 5 ) \div (9 + 2) }}\)
\(= {\sf{(11 ) \div (11) }}\)
\(= {\sf{11 \div 11}}\)
\(={\underline{\boxed{\tt{\red{1}}}}}\)
Hence, the answer is 1.
\(\begin{gathered}\end{gathered}\)
\(2) \: \pmb{\sf{17 - 5 \times 2 \div \sqrt{100}}}\)
\({\sf{ = 17 - 5 \times 2 \div \sqrt{100}}}\)
\({\sf{ = 17 - 5 \times 2 \div \sqrt{2 \times 2 \times 5}}}\)
\({\sf{ = 17 - 5 \times 2 \div \sqrt{ \underline{2 \times 2}\times \underline{5}}}}\)
\({\sf{ = 17 - 5 \times 2 \div (2 \times 5)}}\)
\({\sf{ = 17 - 5 \times 2 \div 10}}\)
\({\sf{ = 17 - 5 \times 0.2}}\)
\({\sf{ = 17 - 1}}\)
\(={\underline{\boxed{\tt{\red{16}}}}}\)
Hence, the answer is 16.
\(\underline{\rule{220pt}{3pt}}\)
