The horizontal distance (s)= ut+\(\frac{1}{2} g t^{2}\)
Time taken by the ball to hit the ground,
h=\(\frac{1}{2} g t^{2}\)
h=60
60= \(\frac{1}{2}*10* t^{2}\)
60=5\(t^{2}\)
\(t^{2}= \frac{60}{5}\)
t=\(\sqrt{12}\)
Replacing for distance covered
H=ut+\(\frac{1}{2} g t^{2}\)
H=3.9m/s*\(\sqrt{12} + \frac{1}{2} *10* \sqrt{12}^{2}\)
H=13.51+60
=73.51 m
