63.5 grams of alcohol having a density of 0.818 g/ml are require for a chemical reaction. How many milliliters of alcohol should be measured out?
mass = 63.5 grams
density = 0.818 g/mL
D = m / V
0.818 = 63.5 / V
V = 63.5 / 0.818
V = 77.628 mL
hope this helps!
To solve this question, we must understand what density is all about.
The density of a substance is simply defined as the mass of the subtance per unit volume of the subtance. Mathematically, the density of a subtance can be expressed as:
\(Density = \frac{Mass}{Volume}\)
With the above formula, we can obtain the volume of alcohol that should be measured out. This can be obtained as illustrated below:
Mass of alcohol = 63.5 g
Deity of alcohol = 0.818 g/mL
\(Density = \frac{Mass}{Volume}\\\\0.818 = \frac{63.5}{Volume}\)
Cross multiply
\(0.818 * Volume = 63.5\)
Divide both side by 0.818
\(Volume = \frac{63.5}{0.818}\)
Therefore, 77.6 mL of alcohol should be measured out.
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