The population (in thousands) of a colony of bacteria t minutes after the introduction of a toxin is given by the function.P(t) =

t^2 + 4 if 0 ≤ t < 5

−5t + 54 if t ≥ 5.

When does the colony die out?

The colony die out when the population becomes 0. i.e. P(t) = 0.
-5t + 54 = 0
5t = 54
t = 54/5
t = 10.8

Therefore, the collony will die out after 10.8 minnute (10 minutes 48 seconds)

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Ckaranja Ckaranja · Answer 2 · 2016-10-07T05:17:55-04:00

Ckaranja Ckaranja

07-10-2016

P(t)=\(-5t+54\)
When t= 11 or exceeds 11, then the colony dies out.
ie
p(11)=-5(11)+54
P(11)=-55+54
P(11)=-1

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The population (in thousands) of a colony of bacteria t minutes after the introduction of a toxin is given by the function.P(t) = t^2 + 4 if 0 ≤ t < 5−5t + 54 if t ≥ 5.When does the colony die out?

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Related Questions

The population (in thousands) of a colony of bacteria t minutes after the introduction of a toxin is given by the function.P(t) =

t^2 + 4 if 0 ≤ t < 5

−5t + 54 if t ≥ 5.

When does the colony die out?