Jon has painted 4/5 of his house. The next day he painted 2/3 of what he had left. What fraction of the house is left to paint?
Jon has painted 4/5 of his house at the first day. Then
\(1-\dfrac{4}{5} =\dfrac{5}{5} -\dfrac{4}{5} =\dfrac{1}{5}\)
left.
The next day he painted 2/3 of what he had left. This is exactly 2/3 from 1/5. Mathematically you should multiply these two fractions:
\(\dfrac{2}{3}\cdot \dfrac{1}{5} =\dfrac{2\cdot 1}{3\cdot 5} =\dfrac{2}{15}\)
he has painted the second day.
Now count how much he has painted at first and second days:
\(\dfrac{4}{5}+\dfrac{2}{15}=\dfrac{4\cdot 3+2}{15}=\dfrac{14}{15} .\)
Then he has to paint
\(1-\dfrac{14}{15} =\dfrac{15}{15}-\dfrac{14}{15}=\dfrac{1}{15} .\)
Answer: \(\dfrac{1}{15} .\)
Answer:
\(\displaystyle\frac{1}{15}\text{ fraction of the house is left to paint.}\)
Step-by-step explanation:
We are given the following information in the question:
Amount of house painted by John = \(\displaystyle\frac{4}{5}\)
House left to be painted =
\(1-\displaystyle\frac{4}{5} = \frac{1}{2}\)
The next day he painted 2/3 of what was left.
House painted next day =
\(\displaystyle\frac{1}{5}\times \frac{2}{3} = \frac{2}{15}\)
Fraction of the house is left to paint =
\(1 - \displaystyle\frac{4}{5}-\frac{2}{15} = \frac{15-12-2}{15} = \frac{1}{15}\)
\(\displaystyle\frac{1}{15}\text{ \bold{fraction of the house is left to paint.}}\)