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The North American and European plates of the

Earth’s crust are drifting apart with a relative speed of

about 25 mm/yr. Take the speed as constant and find when

the rift between them started to open, to reach a current

with of 2.9 x 10^3 mi.

Verified Answer :

Use Xf=Xi+Vxt
(2.9x10^3)=0+(1.55x10^-5)t <------- need to convert 25mm/yr to miles (1mm=6.2137x10^-7)
Solve for t.
t=187,096,774 years

Explanation:

It is given that,

The North American and European plates of the  Earth’s crust are drifting apart with a relative speed of  about, v = 25 mm/ yr

We know that, \(1\ mm/yr=3.171\times 10^{-11}\ m/s\)

\(v=7.927\times 10^{-10}\ m/s\)

Distance between them, \(d=2.9\times 10^3\ mi\)

1 mile = 1609.34 meters

\(d=2.9\times 10^3\ mi=4667098\ m\)

Let t is the time when  the rift between them started to open. Speed is given by distance travelled divided by time taken.

\(t=\dfrac{d}{v}\)

\(t=\dfrac{4667098\ m}{7.927\times 10^{-10}\ m/s}\)

\(t=5.88\times 10^{15}\ s\)

Since, \(1\ s=3.17\times 10^{-8}\ yr\)

So, \(t=18.63\times 10^7\ years\)

or

t = 1.86 million years

Hence, this is the required solution.