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A quadratic equation is shown below:


9x2 − 36x + 36 = 0


Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)


Part B: Solve 2x2 − 9x + 7 = 0 using an appropriate method. Show the steps of your work and explain why you chose the method used. (5 points)

Verified Answer :

apologiabiology

A.
radicand or determinant is if have equation
ax^2+bx+c=0
determinant is
\(b^2-4a}\)
if \(b^2-4ac\)>0, then you have 2 real roots
if \(b^2-4ac\)=0, then you ahve 1 real root
if \(b^2-4ac\)<0, then you ahve 2 complex roots

9x^2-36+36
a=9b
b=-36
c=36

\((-36)^2-4(9)(36)\)
\((-36)^2-(36)(36)\)
we can see that they cancel out and therefor \(b^2-4ac\)=0
there is 1 real root


B. factor
(2x-7)(x-1)=0
set each to zero
2x-7=0
2x=7
x=7/2

x-1=0
x=1

x=7/2 and 1

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