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Two balloons having the same charge of 1.2 × 10-6 coulombs each are kept 5.0 × 10-1 meters apart. What is the magnitude of the repulsive force between them? (k = 9.0 × 109 newton·meter2/coulombs2)


1.2 × 10-2 newtons


3.2 × 10-3 newtons


6.5 × 10-3 newtons


3.0 × 10-4 newtons


5.2 × 10-2 newtons

Verified Answer :

itsmyattitude22

Steps:

1)Data:
q1=charge of first balloon=1.2 × 10^-6
q2=charge of second balloon=1.2 × 10^-6

Condition:q1=q2
then for convenience,we say q instead of q1 and q2.
Radius=r=510^-1
Radius is the distance between balloons!
Magnitude of repulsive force=F=?

2)Solution:
F=kq1q2/r^2
As q1=q2=q
So
F=kqq/r^2
=kq^2/r^2
Putting values:
F=((910^9)(1.2 × 10^-6)^2)/(5*10^-1)^2
Using calculator:
F=0.05184 N

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