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Cu + H2O --> CuO + H2


This equation shows that Cu is either oxidized or reduced? (Choose one)


This equation shows that H2 is either oxidized or reduced? (Choose one)

Verified Answer :

Hagrid

In the reduction-oxidation reaction given, Cu is reduced because it gained 2 electrons, on the other hand H2 is oxidized because it gained one electron. I hope this helps.

Answer: Copper is getting oxidized and hydrogen is getting reduced.

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of this substance is increased and the substance gets oxidized.

\(X\rightarrow X^{n+}+ne^-\)

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of this substance gets reduced and the substance gets reduced.

\(X^{n+}+ne^-\rightarrow X\)

The given chemical reaction is:

\(Cu+H_2O\rightarrow CuO+H_2\)

The half reactions for the given above chemical reaction is:

Oxidation half reaction:  \(Cu\rightarrow Cu^{2+}+2e^-\)

Reduction half reaction:  \(2H^++2e^-\rightarrow H_2\)

As, copper is loosing electrons. so, it is getting oxidized and hydrogen is gaining electrons. So, it is getting reduced.

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