taloniquinnie taloniquinnie

23-09-2016
Mathematics

Answered

Find (f^-1)'(a):

f(x) = 3+x^2+tan(pi(x)/2),

-1

Verified Answer :

Hussain514 Hussain514

27-09-2016

(f^-1)'(a)=1/f'(f^-1)'(a)
f(a) =3 = 3+x^2+tan(pi(x)/2),
0= 3+x^2+tan(pi(x)/2)
(f^-1)'(a)
= 1/[f ' ( f^-1(a) )]

(f^-1)'(3)
= 1/[f ' ( f^-1(3) )]

(f^-1)'(3)
= 1/[f ' ( 0 )]

(f^-1)'(3)
=0+1/2pie(1)
=pi/2
hope it helps

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