Answer:
The answer is C. \(log_2(32)=5\)
Step-by-step explanation:
The logarithmic form is:
\(log_b(x)=y\\b^y=x\\\)
Where:
b is the base of the logarithmic.
In this case, the base could be "2" because the left side of the equation has a 2 powered by 5 and the right side of the equation has a 32 that is equal to 2 powered by 6. Also we can apply the next property:
\(log(a^b)=b*log(a)\)
So, we have to reverse the form from exponential to logarithmic.
Then:
\(2^5=32\\log_2(2^5)=log_2(32)\\5*log_2(2)=log_2(32)\\5*1=log_2(32)\\log_2(32)=5\)
Finally, the equation in logarithmic form is C. \(log_2(32)=5\)
