je5nsynaols
Answered

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

Ax __>__ 9
B9_<__ x
CA number line with a closed circle on 9 and shading to the left.

D ) A number line with a closed circle on 9 and shading to the right.

Verified Answer :

\(2x+2 \geq 20 2x \geq 18 x \geq 9 9 \leq x\) which  is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.

calculista

Answer:

option C

A number line with a closed circle on  \(9\) and shading to the left

Step-by-step explanation:

we have

\(2(x+1)\geq 20\)

solve for x

\(2x+2\geq 20\)

Subtract \(2\) both sides

\(2x+2-2\geq 20-2\)

\(2x\geq 18\)

Divide by \(2\) both sides

\(x\geq 9\) --------> is equivalent to \(9 \leq x\)

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to \(9\)

A number line with a closed circle on  \(9\) and shading to the right

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