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Verified Answer :

\(\frac{ 3-6-2 \sqrt{18} }{ -3 } = -3-6 \sqrt{2} /-3=1+2 \sqrt{2}\)
You amplify with sqrt(3)-sqrt(6).
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Answer: The answer is \(-3+\dfrac{2}{3}\sqrt{18}.\)

Step-by-step explanation:  The given expression is

\(E=\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+\sqrt 6}.\)

we will be rationalising the given expression as follows:

\(E\\\\\\=\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+\sqrt 6}\\\\\\=\dfrac{(\sqrt 3-\sqrt 6)^2}{(\sqrt 3+\sqrt 6)(\sqrt 3-\sqrt 6)}\\\\\\=\dfrac{3-2\sqrt {18}+6}{3-6}\\\\\\=\dfrac{9-2\sqrt{18}}{-3}\\\\\\=-3+\dfrac{2}{3}\sqrt{18}.\)

Thus, the answer is \(-3+\dfrac{2}{3}\sqrt{18}.\)