Answer:
H₂O + 2AgO + 2e⁻ → Ag₂O + 2OH⁻
Explanation:
- First, we write the half reaction:
AgO → Ag₂O
- Then we balance the metal ( in this case it's Ag):
2AgO → Ag₂O
- Next we add H₂O to balance O:
2AgO → Ag₂O + H₂O
- Then we add H⁺ to balance H:
2H⁺ + 2AgO → Ag₂O + H₂O
- Because the solution is basic, we add OH⁻ to both sides, in order to cancel out the H⁺ (In this case we add 2 OH⁻):
2H₂O + 2AgO → Ag₂O + H₂O + 2OH⁻, we cancel H₂O on both sides:
H₂O + 2AgO → Ag₂O + 2OH⁻
- Finally we add electrons to balance charges:
H₂O + 2AgO + 2e⁻ → Ag₂O + 2OH⁻
Now the equation is balanced, both sides have the same number of atoms and the same charge.
