we know that
The volume of a cylinder is equal to
\(V=\pi r^{2} h\)
where
r is the radius of the base
h is the height of the cylinder
In this problem
\(h=3+4r\)
For \(r=2\ in\)
Find the value of h
\(h=3+4*2\)
\(h=11\ in\)
Find the volume of the cylinder
\(V=\pi*2^{2}*11\)
\(V=44*\pi\ in^{3}= 138.2\ in^{3}\)
therefore
the answer is
The volume of a cylinder is equal to \(138.2\ in^{3}\)
