nathanvida
Answered

What is the value for ∆Soreaction for the following reaction, given the standard entropy values?


C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(l)



+131 J/K

-131 J/K

+262 J/K

-262 J/K

+417 J/K

Verified Answer :

taskmasters

The standard entropy for the substances are as follows:

C6H12O2(s) = -212 
O2(g) = -205 
CO2(g) = -214 
H2O(l) = -70

We calculate the ∆S°reaction by the expression:

∆S°rxn = ∆S°products - ∆S° reactants 
∆S°rxn = (212+6x205)-(6x214+6x70) 
∆S°rxn = -262 J/K ------> OPTION 3

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