x+2y+3z=6y+2z=0z=0
x + 2y + 3z = 6 . . . (1)y + 2z = 0 . . . (2)z = 0 . . . (3)Putting (3) into (1) and (2) gives,x + 2y = 6 . . . (4)y = 0 . . . (5)Putting (5) into (4) givesx = 6Therefore, x = 6, y = 0, z = 0
