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salimsalvin
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The size, S, of a tumor (in cubic millimeters) is given by S=2^t, where t is the number of months since the tumor was discovered. Give units with your answers.

AWhat is the total change in the size of the tumor during the first 9 months?

Answer: The total change is

and its units = .

BWhat is the average rate of change in the size of the tumor during the first 9 months?

Answer: The average rate of change is


,

and its units = .

CUse an interval of 0.001 to approximate the rate of change at which the tumor is growing at t=9.

Answer: The rate is


,

Verified Answer :

bramer11
Ayou just do 2^9 which is 512 cubic millimeters
b) using the average rate of change formula you get 56.78 cubic millimeters per month
c) I do not understand at all I am stuck on the same one
MrRoyal

The total change in size in the first 9 months is 512, and the average rate in the first 9 months is 56.89

The function is given as:

\(S = 2^t\)

In the first 9 months, the total change in size is calculated as:

\(S = 2^9\)

This gives

S = 512

The average rate in the first 9 months is then calculated as:

\(S' = \frac{S(9)}{9}\)

Substitute 512 for 2^9

\(S' = \frac{512}{9}\)

Evaluate

S' = 56.89

Read more about average rates at:

https://brainly.com/question/8728504

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