taeilniverse taeilniverse

21-09-2016
Mathematics

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nobillionaireNobley nobillionaireNobley

24-09-2016

Sum of interior angles of a quadrilateral = 360 degrees.

x + 10 + x + 10 + 2x + 50 + 2x + 50 = 360
6x + 120 = 360
6x = 360 - 120 = 240
x = 240/6 = 40
x = 40

A = D = 2(40) + 50 = 80 + 50 = 130 degrees
B = C = 40 + 10 = 50 degrees

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