solve for n -10+log3 (n+3)=-10
remember\(log_{n}x=y\) means \(n^y=x\)-10+log3(n+3)=-10add 10 to both sideslog3(n+3)=0convert\(3^0=n+3\)remmember that anything to 0 power equals 11=n+3minus 3 both sides-2=n