Odina walked down the hall at school from the cafeteria to

the band room, a distance of 100.0 m. A class of physics

students recorded and graphed her position every 2.0 s,

noting that she moved 2.6 m every 2.0 s. When was Odina

in the following positions?

A25.0 m from the cafeteria
B25.0 m from the band room
CCreate a graph showing Odina’s motion.

Verified Answer :

I think no 1 not sure

Answer:

Explanation:

As we know that when graph is plotted with the position and time then it shows that it will move with uniform speed

So here it is moving 2.6 m in 2 s

so speed is given as

\(v = \frac{2.6}{2}\)

\(v = 1.3 m/s\)

Part a)

when she reach 25 m from cafeteria

time taken by her

\(t = \frac{d}{v}\)

\(t = \frac{25}{1.3}\)

\(t = 19.2 s\)

Part b)

When she will reach 25 m from band room

then total distance moved from cafeteria is

\(d = 100 - 25 = 75m\)

time taken by her

\(t = \frac{75}{1.3}\)

\(t = 57.7 s\)

Part c)

Since Odina is moving at constant speed

so the position time graph must be a straight line graph

View image aristocles