Verified Answer :

Molar mass MgS2O3 =  136.43 g/mol


185 g x 1 mole MgS2O3 / 136.43 => 1.356 moles

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Answer: The number of moles of \(MgS_2O_3\) is 1.36 moles.

Explanation:

To calculate the number of moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)

Given mass of \(MgS_2O_3\) = 185 g

Molar mass of \(MgS_2O_3\) = 136.43 g/mol

Putting values in above equation, we get:

\(\text{Moles of }MgS_2O_3=\frac{185g}{136.43g/mol}=1.36mol\)

Hence, the number of moles of \(MgS_2O_3\) is 1.36 moles.