How many moles of MgS2O3 are in 185 g of the compound?
Molar mass MgS2O3 = 136.43 g/mol
185 g x 1 mole MgS2O3 / 136.43 => 1.356 moles
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Answer: The number of moles of \(MgS_2O_3\) is 1.36 moles.
Explanation:
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)
Given mass of \(MgS_2O_3\) = 185 g
Molar mass of \(MgS_2O_3\) = 136.43 g/mol
Putting values in above equation, we get:
\(\text{Moles of }MgS_2O_3=\frac{185g}{136.43g/mol}=1.36mol\)
Hence, the number of moles of \(MgS_2O_3\) is 1.36 moles.