Answer:
B. greater mean = class B greater median = class B
Step-by-step explanation:
Stem and Leaf Plots : It is a special table where each data value is split into a stem (the first digit or digits) and a leaf (usually the last digit).
So, in the given plot for class A
The first stem 4 has leafs = 1,5
The numbers will be 41,45
The second stem 5 has leafs = 1,6,8
The numbers will be 51,56,58
The third stem 6 has leafs = 5,7,7,9
The numbers will be 65,67,67,69
The fourth stem 7 has leafs = 6,6,7,8,9
The numbers will be 76,76,77,78,79
The fifth stem 8 has leafs = 1,2
The numbers will be 81,82
The sixth stem 9 has leafs = 1
The number will be 91
So, The data of class A = 41,45,51,56,58,65,67,67,69,76,76,77,78,79,81,82,91
Thus MEAN of class A = Sum of all scores scored by students / Total No of students whose marks are given
⇒\(\frac{41+45+51+56+58+65+67+67+69+76+76+77+78+79+81+82+91}{17}\)
\(\frac{1159}{17}\)
\(68.17\)
Thus mean of class A = 68.17
Median =The "median" is the "middle" value in the list of numbers.
Since 9th term is the middle value .
So, MEDIAN of class A = 69
The given plot for CLASS B :
The first stem 4 has leafs = 2
The numbers will be 42
The second stem 5 has leafs = 4
The numbers will be 54
The third stem 6 has leafs = 1,6
The numbers will be 61,66
The fourth stem 7 has leafs = 2,5,6,6
The numbers will be 72,75,76,76
The fifth stem 8 has leafs = 0,0,4,8,9
The numbers will be 80,80,84,88,89
The sixth stem 9 has leafs = 3,5,6,7
The number will be 93,95,96,97
So, The data of class B = 42,54,61,66,72,75,76,76,80,80,84,88,89,93,95,96,97
Mean of class B = \(\frac{42+54+61+66+72+75+76+76+80+80+84+88+89+93+95+96+97}{17}\)
⇒\(\frac{1324}{17}\)
⇒ \(77.88\)
Thus mean of class B is 77.88
Median of class B = 9th term = 80
Hence , mean of class A = 68.17 and median of class A = 69
Mean of class B = 77.88 and median of class B = 80
Thus Option B is correct .
Greater mean = class B
Greater median = class B
