The velocity gained by the car is the same, over the given periods
therefore, the work required to change the velocity would be the same.
The true statements are;
- The change in energy for both process is the same
- Both process take the same amount of energy
Reasons:
The amount of work done from in accelerating from 0 to 60 mph is given
by the kinetic energy gained (the change in kinetic energy)
\(\mathrm{Change \ in \ kinetic \ energy, \Delta K.E.} = \dfrac{1}{2} \cdot m \cdot v_f^2 - \dfrac{1}{2} \cdot m \cdot v_i^2\)
Where;
m = Mass
\(v_i\) = The initial velocity
\(v_f\) = The final velocity
Which gives;
Work done by, W, accelerating in 10 seconds, is given as follows;
\(\Delta K.E. = W_{10 \, seconds} = \dfrac{1}{2} \cdot m \times 60^2 - \dfrac{1}{2} \cdot m \times 60^2 = 1800 \cdot m\) -
Work done by, W, accelerating in 30 seconds, is given as follows;
\(\Delta K.E. = W_{30 \, seconds} = \dfrac{1}{2} \cdot m \times 60^2 - \dfrac{1}{2} \cdot m \times 60^2 = 1800 \cdot m\) -
Therefore;
- The change in energy for both process is the same
- Both process take the same amount of energy
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https://brainly.com/question/15598542
