Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
\(5x+2y=10\) (1)
And \(3x+2y=6\) (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
\(15x+6y=30\) (3)
\(15x+10y=30\) (4)
Now subtract (4) from (3) we get:
\(-4y=0\)
\(y=0\)
Now, put y=0 in (1) equation:
\(5x+2(0)=10\)
\(5x=10\)
\(x=2\)
Hence, x=2 and y=0
