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meerkat18

The question is asking to write x^2-8x+13 in the form of (x-1)2 = b where as a and b are integers, base on the said formula, I would say that the correct answer would be (x - 4)2 = 3, I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications 

Answer:

A) \((x - 4)^2 = 3\)

Step-by-step explanation:

The given equation is \(x^{2} -8x +13 = 0\)

We have to convert this quadratic equation in the form of \((x -a)^{2} = b\).

Here we have to use the completing square method.

Identify the value of b from the given quadratic equation.

b = -8 now divide it by 2 and square it.

\((\frac{b}{2})^{2}\)

= \((\frac{-8}{2} )^2\)

= \((-4)^{2}\)

= 16

Now add 16 on both side of the equation

\(x^{2} - 8x + 16 + 13 = 16\)

\((x^{2} -8x +16) +13 = 16\)

Now subtract 13 on both sides, we get

\((x^{2} - 8x +16) + 13 -13 = 16 -13\)

\(x^{2} -8x + 16 = 3\)

Here \((x -4)^{2} = x^2 -8x +16\)

So, we get

\((x - 4)^2 = 3\)

Therefore, answer is A) \((x - 4)^2 = 3\)

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