Answer:
option (4) is correct.
the given expression \(9x^2y-4x+3y^3x-2y^2\) can be written in standard form as \(3y^3x+9x^2y-2y^2-4x\).
Step-by-step explanation:
The Standard form of writing an equation,
1) Look at the degree of each term.
2) You then write each term in order of degree, from highest to lowest, left to right..
3) The expression \(x^2y\) has an exponent of 2 on the x and an unwritten exponent of 1 on the y, so this term is to the third degree (2+1). We add the two degrees together because it has two variables.
Consider the given equation,
\(9x^2y-4x+3y^3x-2y^2\)
We have to write it in standard form using the steps stated above,
first we find the degree of each term in the given expression,
The expression \(x^2y\) has an exponent of 2 on the x and an unwritten exponent of 1 on the y, so this term is to the third degree (2+1).
The expression \(y^3x\) has an exponent of 3 on the y and an unwritten exponent of 1 on the x, so this term is to the third degree (3+1).
So the highest degree in the given expression is \(3y^3x\)
write each term in order of degree, from highest to lowest, left to right.
following this , we can write the expression as,
\(3y^3x+9x^2y-2y^2-4x\)
Thus, option (4) is correct.
