Complete the square:x^2 + 2x - 3 = 0
I got x=plus or minus 1
\(x^{2} +2x-3=0 \\\\ (x)^2+2(x)(1) +(1)^2 -1^2-3 =0 \\\\ (x+1)^2-4 = 0 \\\\ (x+1)^2 = 4 \\\\ x+1 = \± \sqrt{4} \\\\ x = -1 ~\±2 \\\\ \therefore x = 1 ~~~or~~~ x = -3\)
