How do you solve 2x(x+3)=(x+1)(2x-5)
distribute and get 2x^2+6x=2x^2+2x-5x-5 add like terms and get 2x^2+6x=2x^2-3x-5subtract 2x^2 from both sides and get6x=3x-5subtract 3x from both sides3x=5divide both sides by 3 x=5/3
