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Verified Answer :

(2p + 7)(3p^2 + 4p - 3) = 2p(3p^2 + 4p - 3) + 7(3p^2 + 4p - 3) =
6p^3 + 8p^2 - 6p + 21p^2 + 28p - 21 =
6p^3 + 29p^2 + 22p - 21 <===

Answer:

\(6p^{3} +29p^{2} +22p-21\)

Step-by-step explanation:

This is a polynomial product where we have to apply distributive property and exponent properties (image is attached).

So, applying distributive property:

\((2p + 7)(3p^{2}  + 4p-3)\\6p^{3}+8p^{2}-6p+21p^{2}+28p-21\)

Then, we reduce like terms:

\(6p^{3} +29p^{2} +22p-21\)

Therefore, the product is

\(6p^{3} +29p^{2} +22p-21\)

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