The correct answer to the question is : B) 1.94 Km.
EXPLANATION:
As per the question, the car travels 30.25 Km due west.
The car drives 7.50 km up a hill.
The angle of inclination of the hill with the ground is \(\theta=\ 15^{0}\).
We are asked to calculate the vertical displacement of the car.
Resolving 7.50 Km into horizontal and vertical components, we get-
(a) \(7.50cos\theta\) which is the horizontal component.
(b) \(7.50 sin\theta\) which is the vertical component.
The vertical displacement [ y ] is calculated as -
y = \(7.50sin\theta\)
= 7.50sin15
= 1.9411.. m.
= 1.94 m.
Hence, the vertical displacement is 1.94 m.
