Becky has been tracking the population of a town. The population was 5,340 last year and has been increasing by 1.75 times each year. How can Becky develop a function to model this?

Af(x) = (5340 • 1.75)^x where 1.75 is the rate of growth

Bf(x) = 1.75(5340)^x where 5340 is the rate of growth

Cf(x) = 5340(x)^1.75 where 5340 is the rate of growth

Df(x) = 5340(1.75)^x where 1.75 is the rate of growth

the population grows at rate of 1.75
multiply it by this rate every year
As in year 3 it would be 5340(1.75)(1.75)(1.75)
the function is 5340(1.75)^x
f(x) = 5340(1.75)^x where 1.75 is the rate of growth
so D is right answer

Answer Link

jainveenamrata jainveenamrata · Answer 2 · 2022-06-07T05:01:57-04:00

Becky develops a function to model will be f(x) = 5340 (1.75)ˣ.

What is an exponent?

Consider the function:

y = a(1 ± r)ˣ

where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is a plus sign, then there is exponential growth happening by r fraction or 100r %

If there is a minus sign, then there is exponential decay happening by r fraction or 100r %

Becky has been tracking the population of a town. The population was 5,340 last year and has been increasing by 1.75 times each year.

Then the function can be given as

f(x) = 5340 (1.75)ˣ

Then the correct option is D.

More about the exponent link is given below.

https://brainly.com/question/5497425

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