Explanation:
The given data is as follows.
P = 203 k Pa, V = 2.5 L
T = 373 K, n = ?
R = 0.0821 atm L/ K mol
Convert pressure from k Pa to atm as follows.
\(\frac{203 k Pa}{1} \times \frac{1 atm}{101.3 k Pa}\) = 2.00 atm
Now, using the ideal gas equation we will calculate the number of moles as follows.
PV = nRT
n = \(\frac{PV}{RT}\)
= \(\frac{2.00 atm \times 2.5 L}{0.0821 atm L/ K mol \times 373 K}\)
= \(\frac{5}{30.62}\) mol
= 0.163 mol
Thus, we can conclude that number of moles in the given gas sample is 0.163 mol.
