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HomertheGenius

\(\frac{4m ^{3} }{3m ^{2} n}* \frac{9n ^{2} }{30m^{2}n^{2} } = \\ \frac{36m ^{3} n ^{3} }{90m ^{4}n ^{3} }\)
After that 36 and 90 can both be divided by 18 and:
m^3/m^4 = 1/m;  n^2/n^3 = 1/n;
... = \(\frac{2}{5mn}\)
Answer:  4 )

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