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Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Dave’s. What were their scores?


Which is a system of equations to model the problem if x represents Dave’s score and y represents Allan’s score?

Ax + y = 60

y = 2x – 375

Bx + y = 375

y = 2x – 60

Cx + y = 375

y = 2x + 60

Dx – y = 375

y = 2x – 60

Verified Answer :

A system of equations is:
B ) 
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allans score was 230 and Daves score was 145.

Answer:

B. x + y = 375

y = 2x – 60

Step-by-step explanation:

Given :Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Dave’s.

To Find:

What were their scores?

Which is a system of equations to model the problem if x represents Dave’s score and y represents Allan’s score?

Solution :

x repesents Dave’s score

y represents Allan’s score

Since we are given that their combined total score for one game was 375 points

⇒x+y=375 ---1

Now we are given that Allan’s score was 60 less than twice Dave’s

⇒y =2x-60---2

Thus x+y=375 and y =2x-60 is a required system of equations.

So, option b is correct.

Now to calculate their scores.

Put value of y from equation 2 in 1

⇒x+(2x-60)=375

⇒3x=375+60

⇒3x=435

⇒\(x =\frac{435}{3}\)

⇒x=145

Now put this value of x in equation 1 to get value of y

⇒145+y=375

⇒y=375-145

⇒y=230

Thus Dave's score is 145 and Allan's score is 230