2) s(t) = 155tcos(23°)
=> s(1.4) = 155 1.4 cos(23°)
=> s(1.4) ≈ 199.7 ft (1 dp) <=- distance displaced horizontally
a(t) = -32 ft/s^2
=> v(t) = -32t + 155sin(23°)
=> h(t) = -16t^2 + 155tsin(23°)
=> h(1.4) = -16(1.4)^2 + 155(1.4)sin(23°)
=> h(1.4) ≈ 53.4 ft (1 dp) <== distance displaced vertically.