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What is the reduction half-reaction for the following unbalanced redox equation?


Cr2O2 2- + NH3 + → Cr2O3 + N2

ACr2O3 →Cr2O72-


BNH4+ → N2


CN2 → NH4+


DCr2O72- →Cr2O3

Verified Answer :

First find the oxidation states of the various atoms: 
in Cr2O2 2- Cr @ +1; In NH3 N @ +3; in CrO3 Cr @ +3, N2 N @ 0 
Note that N gained electrons, ie, was reduced; Cr was oxidized 
Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out 
B.NH4+ → N2 

Which of the following is an oxidation half-reaction? 
A.Sn 2+ →Sn 4+ + 2e- 
Sn lost electrons so it got oxidized

CN2 → NH4+ would be the correct option