Answer:
\(molec_{water}=6.016*10^{24}molecules\)
Explanation:
Hi, here I explain step by step:
1) You have 263 g/mol and 68.4% of that (in weight) is water. So for 1 mol:
\(m_{water}=0.684*263 g\)
\(m_{water}=179.89 g\)
2) A mol of water molecules weights 18 g/mol (16 g/mol of oxygen and 2g/mol of hydrogen):
\(n_{water}=\frac{179.89g}{18g/mol}\)
\(n_{water}=9.99 mol\)
3) Knowing Avogadro's number: 6.022*10^23 molec/mol:
\(molec_{water}=9.99 mol*6.022*10^{23}molec/mol\)
\(molec_{water}=6.016*10^2^4molec\)
