"2.5 mL" of the suspension are required.
Liquid suspension:
According to the question,
= \(0.125\times 1000\)
= \(125 \ mg\)
- Liquid suspension on hand = 250 mg/5.0 ml
Now,
125 mg present in (Suspension required):
= \((\frac{5.0}{250}\times 125 )\)
= \(2.5 \ mL\)
Thus the above approach is correct.
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