find the 'ones'
remember that x/x=1 when x=x
also \(\frac{a+b}{c} =( \frac{a}{c})+(\frac{b}{c})\)
try to see how many of the deomenator goes in the numerator
91=9
92=18
93=27
94=36
9*5=45
45 is too high
36 is just below
use 36
37-36=1
so
\(\frac{38}{9}\)=
\(( \frac{36}{9} )+( \frac{1}{9} )\)=
\(4+ \frac{1}{9}\)=
4 and 1/9
answer is 4 and 1/9
(who cares about grammer, here's your answer)
