oneray
Answered

A sandbox has an area of 26 square feet, and the length is 5-1/2 feet. What is the width of the sandbox?

Verified Answer :

crisforp

(5 1/2) x width = 26;
Then, (11/2) x width = 26;
width = 26 ÷ (11/2);
width = (26x2)/11;
width = 52/11 = 4.72 feet;

Answer:

Width of the sandbox, b = 4.72 feet

Step-by-step explanation:

It is given that,

The area of the sandbox, \(A=26\ ft^2\)

Length of the box, \(l=5\dfrac{1}{2}\ ft=5.5\ ft\)

We need to find the width of the sandbox. The area of the rectangle is given by :

\(A=l\times b\)

b is the width of the sandbox

So, \(b=\dfrac{A}{l}\)

\(b=\dfrac{26}{5.5}\)

b = 4.72 feet

So, the width of the sandbox is 4.72 feet. Hence, this is the required solution.

Related Questions