Answer:24
Step-by-step explanation:
Given: There are at most \(36\) red and blue marbles in a bag. The number of red marbles is twice the number of blue marbles.
To Find: Write and solve an inequality that represents the greatest number of red marbles r in the bag.
Solution:
Let the number of red marble be \(=\text{r}\)
Let the number of blue marble be \(=\text{b}\)
as,
\(\text{r}+\text{b}\leq 36\)
also
\(\text{r}=2\text{b}\)
\(\text{b}=\frac{\text{r}}{2}\)
putting in equation
\(\text{r}+\frac{\text{r}}{2}\)
\(\frac{3}{2}\text{r}\leq36\)
\(\frac{3}{2}\text{r}\leq36\)
\(\text{r}\leq\frac{2}{3}\times36\)
\(\text{r}\leq24\)
Hence there can be atmost \(24\) marble in the bag
